We start with a simple theorem, which gives a tight upper bound on the minimum distance of high-rate cycle-free linear codes.
Proof.
Let H be the
r×n cycle-free parity-check matrix for
.
We assume without loss of generality that H has full row-rank and
that r = n - k, since
otherwise we can remove the linearly dependent rows of H while
preserving the cycle-free property.
Let
denote the number of columns of weight i in H.
If
0 then d = 1, and we are done. Otherwise, we have
at least
Theorem 3.3 implies that the
(n, n-1, 2) code
n, whose parity-check matrix consists of a single all-1 vector,
is, in a sense, the optimal cycle-free code of rate
0.5.
Since all such codes have distance d
2 and
n has the
highest rate. The cycle-free Tanner graph for
n is depicted
in Figure 3.2a.
To show that the bound of Theorem 3.3 is tight for all n and k, with
n/2k
n - 1, we may start with the single-parity-check code
k+1 and repeat any symbol (or symbols)
in
k+1 until
a code of length n is obtained. The following lemma shows that
this always produces an (n, k, 2) cycle-free code for k
n/2.
Proof.
The length and dimension of
are obvious. To see that
is cycle-free, observe that a Tanner graph T' for
can be
obtained from the cycle-free Tanner graph T for
by introducing
two new vertices x' and y' and two new edges: (x', y') and
(xi, y'). Clearly this procedure does not create
new cycles.
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Let
be a cycle-free code of length n, and let
be the
code of length
n +
obtained from
by iteratively
applying
times the procedure of Lemma 3.4, while possibly
choosing a different value of i at different iterations. We then
say that
is a code obtained by repeating symbols
in
.
To make our terminology precise, we further extend the notion of
codes obtained by ``repeating symbols in
'' to also include
the codes obtained from
by appending all-zero coordinates.
The following proposition shows that every low-rate cycle-free
linear code has this structure.
Proof.
Let H be the
r×n cycle-free parity-check matrix for
,
with r = n - k. Then by Lemma 3.2 and (3.2), we have
,
where the second inequality follows from the fact that
k/n
0.5.
This implies that H contains at least one row of
weight
2. If this row is of weight one, then the corresponding
coordinate of
, say the n-th coordinate, is all-zero. Otherwise,
assume without loss of generality that this row is of the form
h = (0, 0,..., 0,*,*).
Then, up to scaling the last two columns of H by constants in
IFq,
we may further assume that
h = (0, 0,..., 0, 1, - 1).
This would mean that the n-th symbol in
is a repetition
of the preceding symbol. In both cases, we can puncture-out the n-th
coordinate of
, and recursively repeat the argument until a cycle-free
code of rate > 0.5 is obtained.
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Loosely speaking, Proposition4 implies that every cycle-free
code
of rate
0.5 can be represented by a Tanner graph
whose structure is shown in Figure 3.2b. The dashed line in Figure 3.2b
encloses a cycle-free Tanner graph for a code
of rate > 0.5
and distance
2.
It follows that to establish a bound on the minimum distance
of low-rate cycle-free codes, we need to determine an optimal choice for
in Figure 3.2b and an optimal sequence of symbol repetitions.
This problem is considered in detail in the next two sections.
Specifically, we will show in Section 3.4 and Section 3.5 that
the single-parity-check code constitutes an optimal choice for
,
and every symbol should be repeated equally often.
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